5m^2-10m-63=0

Solution for 5m^2-10m-63=0 equation:

5m^2-10m-63=0

a = 5; b = -10; c = -63;
Δ = b2-4ac
Δ = -102-4·5·(-63)
Δ = 1360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1360}=\sqrt{16*85}=\sqrt{16}*\sqrt{85}=4\sqrt{85}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{85}}{2*5}=\frac{10-4\sqrt{85}}{10}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{85}}{2*5}=\frac{10+4\sqrt{85}}{10}
$